B^2+11b+(11/2)^2=6+(11/2)^2

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Solution for B^2+11b+(11/2)^2=6+(11/2)^2 equation: 



^2+11B+(11/2)^2=6+(11/2)^2

We move all terms to the left:

^2+11B+(11/2)^2-(6+(11/2)^2)=0

We add all the numbers together, and all the variables

11B+^2+(+11/2)^2-(6+(+11/2)^2)=0

We add all the numbers together, and all the variables

11B+(+11/2)^2-(6+(+11/2)^2)=0

We calculate fractions


11B+()/()+()/()=0

We add all the numbers together, and all the variables

11B+2=0

We move all terms containing B to the left, all other terms to the right

11B=-2

B=-2/11

B=-2/11

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